2y^2-y+8=0

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Solution for 2y^2-y+8=0 equation:


Simplifying
2y2 + -1y + 8 = 0

Reorder the terms:
8 + -1y + 2y2 = 0

Solving
8 + -1y + 2y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
4 + -0.5y + y2 = 0

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + -0.5y + -4 + y2 = 0 + -4

Reorder the terms:
4 + -4 + -0.5y + y2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -0.5y + y2 = 0 + -4
-0.5y + y2 = 0 + -4

Combine like terms: 0 + -4 = -4
-0.5y + y2 = -4

The y term is -0.5y.  Take half its coefficient (-0.25).
Square it (0.0625) and add it to both sides.

Add '0.0625' to each side of the equation.
-0.5y + 0.0625 + y2 = -4 + 0.0625

Reorder the terms:
0.0625 + -0.5y + y2 = -4 + 0.0625

Combine like terms: -4 + 0.0625 = -3.9375
0.0625 + -0.5y + y2 = -3.9375

Factor a perfect square on the left side:
(y + -0.25)(y + -0.25) = -3.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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